Understanding Radioactive Decay: Mathematical Models and Applications

Expert reviewed 22 November 2024 5 minute read


Introduction

Radioactive decay is a fundamental process in nuclear physics where unstable atomic nuclei spontaneously transform into more stable configurations. This process follows precise mathematical models that allow us to predict the amount of radioactive material present at any given time.

The Mathematical Model of Radioactive Decay

The basic model of radioactive decay follows an exponential decay pattern, described by the equation:

Nt=N0eλtN_t = N_0e^{-λt}

Where:

  • NtN_t is the number of radioactive nuclei present at time tt
  • N0N_0 is the initial number of radioactive nuclei (at t=0t = 0)
  • λλ is the decay constant (specific to each isotope)
  • tt is the elapsed time

Half-Life: A Key Concept

The half-life (t1/2t_{1/2}) of a radioactive isotope is the time required for half of the initial amount to decay. This value remains constant throughout the decay process, regardless of the initial quantity.

For example, if we start with 100 atoms:

  • After one half-life: 50 atoms remain
  • After two half-lives: 25 atoms remain
  • After three half-lives: 12.5 atoms remain

The Decay Constant

The decay constant (λλ) is related to half-life through the equation:

λ=ln(2)t1/2λ = \frac{\ln(2)}{t_{1/2}}

This relationship shows that:

  • A larger decay constant means faster decay
  • The decay constant is inversely proportional to half-life

Units in Radioactive Decay Calculations

When performing calculations, it's crucial to maintain consistent units. The following table shows common unit combinations:

Time Unit (t)Decay Constant (λ) Unit
secondss⁻¹
minutesmin⁻¹
hourshr⁻¹
yearsyr⁻¹

Note: The units chosen for time must match the units used in the decay constant.

Sample Problem

Problem: A sample contains 100 kg of Cobalt-60, which has a half-life of 5.30 years. Calculate the remaining mass after 12 years.

Solution:

  • Calculate the decay constant: λ=ln(2)5.30=0.131 yr1λ = \frac{\ln(2)}{5.30} = 0.131 \text{ yr}^{-1}

  • Apply the decay equation: Nt=N0eλtN_t = N_0e^{-λt} Nt=100e(0.131)(12)N_t = 100e^{-(0.131)(12)} Nt=20.8 kgN_t = 20.8 \text{ kg}

Key Points to Remember

  • Radioactive decay follows an exponential pattern
  • Half-life is constant for each isotope
  • The decay constant is unique to each isotope
  • Units must be consistent throughout calculations

Return to Module *: From the Universe to the Atom