The Limiting Sum of a Geometric Series

Expert reviewed 21 July 2024 5 minute read


HSC Maths Advanced Syllabus

  • derive and use the formula for the limiting sum of a geometric series with r<1:S=a1r|r|<1:S=\frac{a}{1-r}
  • understand the limiting behaviour as 𝑛 → ∞ and its application to a geometric series as a limiting sum
  • use the notation limnrn=0\lim_{n \to \infty}r^n=0 for r<1|r|<1

What is the Limiting Sum Formula?

The limiting sum of a geometric sequence, is also known as the sum of an infinite geometric series. This occurs when sum of the sequence increases indefinitely. This only occurs when the absolute value of the common ratio is less than 1, that is: r<1or1<r<1|r|<1\quad or \quad -1<r<1

We use the absolute value of rr, as the common ratio can be a negative number. The purpose of the limiting sum formula, is to determine whether a geometric series with an infinite number of terms, converges to a finite value.

The Limiting Sum Formula

The limiting sum SS_{\infty} of a GP with first term aa and common ratio rr, where

r<1or1<r<1|r|<1\quad or \quad -1<r<1 is given by:

S=a1rS_{\infty}=\frac{a}{1-r}

Practice Question 1

Find the limiting sum of the following GP: 16,8,4,2,1,12,...16,8,4,2,1,\frac{1}{2},...

From the information given, we can see that the first term of the sequence is 16 and the common ratio is 12\frac{1}{2}

Because the common ratio satisfies the identity r<1|r|<1, we can substitute points into the formula above to find the limiting sum of the sequence.

S=16112=1612=32S_\infty=\frac{16}{1-\frac{1}{2}}\\=\frac{16}{\frac{1}{2}}\\=32

Recurring Decimals and GP’s

We can also use the limiting sum formula when dealing with recurring decimals. Recurring decimals are just GP’s that continue infinitely, to a number so small it is essentially zero. We implement the limiting sum formula to convert recurring decimals into fractions.

For example, the recurring decimal 0.330.\overline{33} can be expanded into:

0.33=0.3+0.03+0.003+0.0003+...0.\overline{33}=0.3+0.03+0.003+0.0003+...

As such, we can see that a GP with a first term of 0.30.3 and a common ratio of 0.10.1 has been formed. Thus, we can apply the limiting sum formula.

0.33=a1r=0.310.1=0.30.9=130.\overline{33}=\frac{a}{1-r}\\=\frac{0.3}{1-0.1}\\=\frac{0.3}{0.9}\\=\frac{1}{3}

Thus, in applying the limiting sum formula, we have successfully converted the recurring decimal 0.330.\overline{33} into a fraction 13\frac{1}{3}

Return to Module 1: Sequences and Series