Geometric Sequences

Expert reviewed 21 July 2024 6 minute read


HSC Maths Advanced Syllabus

  • recognise and use the recursive definition of a geometric sequence: Tn=rTn1,T1=aTn = rT_{n-1}, T_1=a
  • establish and use the formula for the nnth term of a geometric sequence: Tn=arn1T_n=ar^{n-1}, where 𝑎 is the first term, 𝑟 is the common ratio and 𝑛 is a positive integer, and recognise its exponential nature

What is a Geometric Sequence?

A geometric sequence or GP for short, is a sequence of numbers where each term after the first, is found by multiplying the previous term by a fixed ratio. This ratio is known as the "common ratio," and is represented by the letter r. A sequence is therefore noted as geometric progression, if the following condition is fulfilled:

r=TnTn1r=\frac{T_n}{T_{n-1}}

Finding the nth Term of a GP

The formula to find the nnth **term of a geometric sequence is given by:

Tn=arn1T_n = ar^{n-1}

Where aa is the first term in the sequence T1T_1 and rr is the common ratio.

Practice Question 1

Find the formula for the nnth term of a geometric sequence, that starts at 2 and has a common ratio of 3.

From the given information we know that a=2a=2 and r=3r=3. Thus,

Tn=2×3n1T_n=2\times 3^{n-1}

Practice Question 2

Determine if the values 54 and 105 are terms of the sequence, defined by the equation found in the previous question.

From the information given, we know that Tn=2×3n1T_n=2\times 3^{n-1}:

Thus, to determine if the terms 54 and 105 are part of this sequence, we must equate them with the formula to find n:

54=2×3n1105=2×3n127=3n152.5=3n1n1=3n1=52.53n=4n=52.53+154 = 2\times3^{n-1} \qquad \qquad 105 = 2\times3^{n-1}\\27=3^{n-1} \qquad \qquad 52.5 = 3^{n-1}\\n-1=3\qquad\qquad n-1=\sqrt[3]{52.5}\\n=4 \qquad\qquad n=\sqrt[3]{52.5}+1

\therefore We can see that 54 is the 4th term of the sequence, and 105 is not a term (as the answer for nn **is not an integer)

Can a GP be Formed Using 3 numbers?

eg

e,f,ge,f,g

We can use the following formulas to determine if the sequence is an GP, and to find any missing variables.

fe=gff2=eg\frac{f}{e}=\frac{g}{f}\qquad\qquad f^2=eg

Practice Question 3

Determine if the following sequence is a GP: 5,10,205,10,20

From the information given, we know that e=5,f=10,g=20e=5, f=10 , g=20.

Substituting in values:

102=5×20100=10010^2=5\times20\\100=100

\therefore By using the given formula we can see that the given sequence is a GP.

(Note: either formula can be used)

Return to Module 1: Sequences and Series