Circular Motion on Banked Surfaces

Expert reviewed 22 November 2024 9 minute read


Forces on a Banked Surface

Circular motion on banked surfaces is a fascinating aspect of physics that combines concepts of circular motion, forces, and inclined planes. To understand circular motion on banked surfaces, we must first analyse the forces at play. Let’s consider an object moving in a circular path on a banked surface without friction.

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The key forces acting on the object are:

  • Weight (W)(W): The downward force due to gravity.
  • Normal force (N)(N): The force exerted by the surface perpendicular to it.

Unlike circular motion on a flat surface, the normal force is not parallel to the weight. This angle between the normal force and the vertical is crucial for maintaining circular motion.

Resolving Forces

We need to resolve the normal force into its horizontal and vertical components:

  • Horizontal component:
Nx=NsinθN_x=Nsin\theta
  • Vertical component: N = Ncos θ
Ny=NcosθN_y=Ncos\theta

Where,

  • θ\theta is the angle of the banked surface relative to the horizontal.

What is the Ideal Velocity for Uniform Circular Motion?

To determine the ideal velocity for uniform circular motion on a banked surface, we analyse the forces in both horizontal and vertical directions.

Horizontal Forces

The horizontal component of the normal force provides the centripetal force required for circular motion:

Nsinθ=mv2r(1)N\sin\theta = \frac{mv^2}{r} … (1)

Where:

  • mm is the mass of the object
  • vv is the velocity
  • rr is the radius of the circular path

Vertical Forces

The vertical component of the normal force balances the weight of the object:

Ncosθ=mg(2)Ncos θ = mg … (2)

Where,

  • gg is the acceleration due to gravity.

Deriving the Ideal Velocity

Dividing equation (1)(1) by equation (2)(2):

NsinθNcosθ=mv2/rmg\frac{N\sin\theta}{N\cos\theta} = \frac{mv^2/r}{mg}

Simplifying:

tanθ=v2rg\tan\theta = \frac{v^2}{rg}

Rearranging for vv:

v=rgtanθv = \sqrt{rg\tan\theta}

This equation gives us the ideal velocity for an object to maintain uniform circular motion on a banked surface without the need for friction.

What are the Factors Affecting Circular Motion on Banked Surfaces?

The ideal velocity depends on three key factors:

  • Radius of the circular path (r)(r): A larger radius allows for higher velocities.
  • Acceleration due to gravity (g)(g): This is typically constant (9.8 m/s² on Earth).
  • Angle of the banked surface (θ)(\theta): A steeper angle allows for higher velocities.

Practice Question 1

A circular highway exit ramp has a radius of 50 m and is banked at an angle of 12°. At what speed can a car navigate this curve without relying on friction?

Identify the given information:

  • Radius, r=50mr = 50 m
  • Angle of bank, θ=12°θ = 12°
  • Acceleration due to gravity, g=9.8m/s2g = 9.8 m/s²

Use the equation for ideal velocity:

v=rgtanθv = \sqrt{rg\tan\theta}

Substitute the values:

v=(50 m)(9.8 m/s²)tan12°v = \sqrt{(50 \text{ m})(9.8 \text{ m/s²})\tan 12°}

Calculate:

v=490tan12°=490×0.213=104.37=10.2m/sv = \sqrt{490 \tan 12°} \\= \sqrt{490 \times 0.213} \\= \sqrt{104.37} \\= 10.2 m/s

Therefore, a car can navigate this curve at a speed of 10.2 m/s (or about 36.7 km/h) without relying on friction.

Practice Question 2

A race track designer wants to ensure that cars can safely navigate a circular turn with a radius of 100 m at a speed of 25 m/s. What is the minimum angle at which the track should be banked to allow this without relying on friction?

Identify the given information:

  • Radius, r=100mr = 100 m
  • Velocity, v=25m/sv = 25 m/s
  • Acceleration due to gravity, g=9.8m/s2g = 9.8 m/s²

Use the equation for ideal velocity and solve for θ:

v=rgtanθtanθ=v2rgv = \sqrt{rg\tan\theta} \tan\theta \\= \frac{v^2}{rg}

Substitute the values:

tanθ=(25)2(100)(9.8)\tan\theta = \frac{(25)^2}{(100 )(9.8 )}

Calculate:

tanθ=625980=0.6378\tan\theta = \frac{625}{980} \\= 0.6378

Find θ using inverse tangent:

θ=tan1(0.6378)=32.5°θ = tan−1(0.6378) = 32.5°

Therefore, the track should be banked at a minimum angle of 32.5° to allow cars to safely navigate the turn at 25 m/s without relying on friction.

Comparison with Flat Surfaces

It’s important to note that the velocity required for circular motion on a banked surface is lower than that needed on a flat surface of the same radius. This is because part of the normal force contributes to the centripetal force, reducing the reliance on friction.

Return to Module 5: Advanced Mechanics