Circular Motion: Analysing a Mass on a String
Expert reviewed • 22 November 2024 • 8 minute read
Review of the Basic Principles of Circular Motion
Before diving into specific scenarios, let’s review some key concepts:
- Uniform Circular Motion: This occurs when an object moves in a circular path with constant speed.
- Centripetal Force: The net force directed toward the centre of the circular path, causing the object to continually change direction.
- Tension: The force exerted by a string or rope when stretched.
In the case of a mass on a string, the tension in the string provides the centripetal force necessary for circular motion.
Horizontal Circular Motion
Consider a mass attached to a string, swinging in a horizontal circle.
Force Analysis
In this scenario, two main forces act on the mass:
- Tension (T): Directed inward along the string.
- Weight (mg): Directed downward due to gravity.
For purely horizontal motion, the tension must be significantly greater than the weight. The centripetal force is provided entirely by the tension:
Fc=T=rmv2
Where:
- Fc is the centripetal force
- m is the mass of the object
- v is the velocity
- r is the radius of the circular path
What are the key Relationships in Circular Motion?
- Tension and Mass: T∝m (directly proportional)
- Tension and Velocity: T∝v2 (directly proportional to squared velocity)
- Tension and Radius: T∝r1 (inversely proportional)
Practice Question 1
A 0.5 kg mass is swung in a horizontal circle with a radius of 1 m at a speed of 4 m/s. Calculate the tension in the string.
T=rmv2=10.5⋅(4)2=8 N
Conical Pendulum: String at an Angle
When the string makes an angle with the vertical, we have a conical pendulum.
Force Analysis
In this case, we need to consider the components of the tension:
- Horizontal component: Tx = Tsin θ (provides centripetal force)
- Vertical component: Ty = Tcos θ (balances weight)
Key Equations
rmv2=Tsinθ
mg = Tcos θ
rgv2=tanθ
From this, we can derive an expression for velocity:
v=rgtanθ
Practice Question 2
A 0.2 kg mass is attached to a 0.8 m string and swung so that it makes a 30° angle with the vertical. Calculate the velocity of the mass.
v=rgtanθ=0.8×9.8×tan30°≈2.13 m/s
Vertical Circular Motion
When a mass on a string is swung in a vertical circle, the analysis becomes more complex due to the changing direction of forces.
Force Analysis
The tension and net force vary depending on the position:
Tt=rmv2−mg
Tb=rmv2+mg
Minimum Velocity
For the mass to complete a vertical circle, there’s a minimum velocity required at the top:
vmin=gr
If the velocity is less than this, the mass will fall before completing the circle.
Key Takeaways
- In circular motion with a mass on a string, tension provides the centripetal force.
- For horizontal motion, tension must be greater than weight.
- In conical pendulum motion, the angle affects the required velocity.
- Vertical circular motion involves varying tension, with a minimum velocity requirement.
- Understanding these principles is crucial for analysing more complex rotational systems.