The Indefinite Integral

Expert reviewed 21 July 2024 6 minute read


HSC Maths Advanced Syllabus

  • determine indefinite integrals of the form f(ax+b)dx\int f(ax+b)dx
  • recognise that any two anti-derivatives of 𝑓(𝑥) differ by a constant

Note:

Video coming soon!

What is the Indefinite Integral?

As discussed in earlier chapters, indefinite integrals are integrals, which are not governed by any limits. In simpler terms, when you take the derivative of an indefinite integral, you get the original function back.

Key Indefinite Integral Formulae

So far in this module, we have explored various integration formulas. However, we must manipulate these formulas to account for the constant CC, which is introduced as part of an indefinite integral. The formulas are as follows:

xndx=1n+1xn+1+Cand(ax+b)n=1a(n+1)(ax+b)n+1+C\int x^ndx=\frac{1}{n+1}x^{n+1}+C\\and\\\int(ax+b)^n=\frac{1}{a(n+1)}(ax+b)^{n+1}+C

There is only one condition where these formulas will not work, and that is when n=1n=-1. Solving integrals under this condition, will be explored in a later module.

What is C?

As seen in the formulas above, we have introduced a new variable to the integration formulas, CC. This is a constant which occurs when you integrate a indefinite integral. This is due to the fact, that when an integral is not defined by limits, the original equation, or the anti-derivative, can be an infinite amount of different possibilities.

For example, the following expression can have infinite solutions, as there are infinite primitive equations which equal the same derivative.

x.dx=x22+Cor=x22+2or=x22+3...\int x.dx=\frac{x^2}{2}+C\\or\\=\frac{x^2}{2}+2\\or\\=\frac{x^2}{2}+3 \\...

As such, we simply integrate, including CC , which can be determined later using various other points, that fit the equation.

Practice Question 1

Integrate the following function: y=(5x+10)4y=(5x+10)^4

Because this equation is in the form (ax+b)n(ax+b)^n, we can use the formula listed above.

(5x+10)4dx=15(4+1)(5x+10)5+C=(5x+10)525+C\int(5x+10)^4dx=\frac{1}{5(4+1)}(5x+10)^5+C\\=\frac{(5x+10)^5}{25}+C

Practice Question 2

If the function found in the previous question, passes through the point (1,10)(1,10), find CC.

Substituting in points:

10=(5(1)+10)525+C10=30375+CC=3036510=\frac{(5(1)+10)^5}{25}+C\\10=30375+C\\C=30365

Integrating Harder Functions

When integrating functions with negative and fractional indices, they can seem tricky to approach as they often appear in the forms 1xn\frac{1}{x^n} and xn\sqrt[n]{x}. However, there is a simple way of solving these problems.

To solve by using the formulas listed above, simply change the form in which they are displayed, as shown below.

1xn=xnxn=x1n\frac{1}{x^n}=x^{-n}\\\sqrt[n]{x}=x^{\frac{1}{n}}

By doing this, the equations given in these forms become simple to integrate. See a hard example completed in the video above.

Return to Module 4: Integration