Introduction to Curve Sketching

Expert reviewed 21 July 2024 4 minute read


HSC Maths Advanced Syllabus

  • use the first derivative to investigate the shape of the graph of a function
    • deduce from the sign of the first derivative whether a function is increasing, decreasing or stationary at a given point or in a given interval

Note:

Video coming soon!

Curve Sketching Notes

Before beginning to use calculus to assist with the sketching of graphs, we need to first understand the nature of a curve.

Any point on a graph can be defined as increasing, decreasing or stationary. To determine the nature of the graph at a certain point, we must find the derivative of the graph (at that point).

For example, Let f(x)f(x) be a function which passes through point pp.

  • If f(p)>0f'(p) >0, the function f(x)f(x) is increasing, when x=px=p
  • If f(p)<0f'(p) <0, the function f(x)f(x) is decreasing, when x=px=p
  • If f(p)=0f'(p) =0, the function f(x)f(x) is stationary, when x=px=p

Practice Question 1

Determine if the function y=3x+5y=\frac{3}{x+5} has any stationary points.

We know that a function is stationary when it’s derivative at a point is equal to 0. Thus, to determine if this function has any stationary points, we must derive it and see at what values of xxoccur, when f(x)=0f'(x)=0:

y=3(x+5)1dydx=1×1×3(x+5)2=3(x+5)2y=3(x+5)^{-1}\\\frac{dy}{dx}=-1\times1\times 3(x+5)^{-2}\\=-\frac{3}{(x+5)^2}

Now that we have found the derivative, we must determine if any points are equal to 0.

0=3(x+5)20=-\frac{3}{(x+5)^2}\\

Looking at this equation, we can see that no value of xx is equal to 0, and as such this graph will have no stationary points.

Return to Module 2: Curve Sketching Using the Derivative