establish and use the formulae ∫x1dx=ln∣x∣+C and ∫f(x)f′(x)dx=ln∣f(x)∣+C for x=0, f(x)=0, respectively
Note:
Video coming soon!
The Reciprocal Function
As we know the reciprocal function is displayed by dxdlogex=x1. By reversing this we can determine the formula to integrate expressions in the form x1. Thus, the formula to integrate the reciprocal function, is as follows:
∫x1dx=logex+C
However, the function x1 can also be negative, and as such, has primitive loge(−x) as well as logex. Thus, we manipulate the formula for integrating the reciprocal function to be:
∫x1dx=loge∣x∣+C
Additionally, there are two other standard formulas used for integrating the reciprocal function.
To be able to solve the integral, we must first determine f(x) and f′(x).
f(x)=5x2+1f′(x)=2×5x2−1=10x
As we can see, the values we have determined, do not yet fit the formulas provided in the chapter above. Thus, we must manipulate the integral to fit the needed form.
When we are asked to solve increasingly difficult integration questions, the process in which we we solve the question can vary slightly. In the video above, we explore this concept, looking at solving the integral: ∫1elogexdx