Graphing: Key Concepts and Revision

Expert reviewed 21 July 2024 10 minute read


HSC Maths Advanced Syllabus

  • use graphical methods with supporting algebraic working to solve a variety of practical problems involving any of the functions within the scope of this syllabus, in both real-life and abstract contexts
    • determine asymptotes and discontinuities where appropriate (vertical and horizontal asymptotes only)

Note:

Video coming soon!

The Sign of a Function

Knowing the sign of a function at a certain point of a given function is important. It can allow you to determine:

  • The functions position above or below the x-axis
  • The true solutions of an inequality
  • Whether a function is increasing/decreasing (which is vital to graph sketching)

A simple way to determine the sign of a function is to create a table of signs for a given equation. This is done by substituting various points, suitable for the given equation, and determining if those points are positive, negative, zero or discontinuities. A discontinuity is shown in the table of signs by text saying "undefined."

For example, the following table of signs is for the function y=1x3y=\frac{1}{x-3} between 3x3-3\leq x\leq3

xx-3-1013
Sign----undefined

The sign row, is found by substituting values of xx into the original equation (according to the given limits) and determining the sign of corresponding values of yy

Vertical and Horizontal Asymptotes

Vertical asymptotes occur where a function approaches infinity or negative infinity as the input of a function approaches a certain value. They indicate points where the function is undefined. On a graph, this would be represented as a dotted line, which no curve can cross.

A simple approach to finding the vertical asymptote/s of a function is to draw up a table of signs for given function and determine where there is a discontinuity for a function. However, there is a quicker and simpler method to determine the vertical asymptotes of a function.

For a rational function written in the form f(x)g(x)\frac{f(x)}{g(x)}, we can find the vertical asymptotes by simply finding the solutions to g(x)=0g(x)=0. However, when doing this you must ensure the equation has been completely simplified, or you could end up finding an incorrect asymptote.

Practice Question 1

Find the vertical asymptote/s of the function f(x)=6x6+22x6128f(x)=\frac{6x^6+2}{2x^6-128}

To find the vertical asymptote we must make the denominator or g(x)=0g(x)=0 and solve.

0=2x61282x6=128x6=64x=646x=±20=2x^6-128\\2x^6=128\\x^6=64\\x=\sqrt[6]{64}\\x=\pm2

\therefore The horizontal asymptotes of the equation occur when x=±2x=\pm2

Horizontal asymptotes describe the behaviour of a function as xx approaches \infty or -\infty, showing the output value that the function approaches. This is generally represented on a graph, by a dotted horizontal line, which no curve can cross. Finding the horizontal asymptotes of a function can be difficult, however, there are three simple steps to follow that can be of assistance.

For a function in the simplest form of f(x)g(x)\frac{f(x)}{g(x)}, the horizontal asymptote can be found when:

  • The denominator’s degree is greater: If the degree of f(x)f(x) is less than the degree of g(x)g(x), then the x-axis is the only horizontal asymptote (y=0)(y=0). Eg.
x21x3+2\frac{x^2-1}{x^3+2}
  • Equal degrees: If f(x)f(x) and g(x)g(x) have the same degree, then the horizontal asymptote is found by dividing the coefficients of the numerator with the largest degree, by that of the denominator; y=aby=\frac{a}{b}, where aa and bb are the respective coefficients. Eg.
5x313x3+253\frac{5x^3-1}{3x^3+2}\\\therefore\frac{5}{3}
  • The numerators degree is greater: If the degree of f(x)f(x) is greater than the degree of g(x)g(x), there is no horizontal asymptote. Eg.
x31x2+2\frac{x^3-1}{x^2+2}

Note that the degree of a function refers to the value of xx in the equation with the highest power. For example, for the function f(x)=x6+x2+2f(x) = x^6+x^2+2 has a degree of 6.

Practice Question 2

Find the horizontal asymptote/s of the function f(x)=6x6+22x6128f(x)=\frac{6x^6+2}{2x^6-128}

From the given equation, we can see that both the numerator and denominator have the same leading degree. Therefore, to find the horizontal asymptote/s we must divide the leading coefficients by each other.

62=3\frac{6}{2}=3

Therefore, the only horizontal asymptote of the function is y=3y=3

Return to Module 2: Graphs and Equations