Average Velocity and Speed

Expert reviewed 21 July 2024 10 minute read


HSC Maths Advanced Syllabus

  • solve optimisation problems for any of the functions covered in the scope of this syllabus, in a wide variety of contexts including displacement, velocity, acceleration, area, volume, business, finance and growth and decay

Note:

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Motion in Various Dimensions

The direction of motion can occur in various dimensions. Motion in one dimension refers to motion that is travelling in one line. This can be seen through the variable xx when written as a function of time (denoted as tt). The variable xx refers to the displacement of an object on a number line.

It is important to know that time can’t be a negative. When a question specifies the use of negative time, it generally means time is travelling backwards. As such, it is highly unlikely to find a question dealing with negative time.

What is Displacement?

Displacement represents the change in position of an object. It is not the same as distance; displacement measures the shortest path between the start and end points, considering direction. Displacement is noted as the letter xx, while the change in displacement is represented by:

Δx=xfinalxintial\Delta x=x_{final}-x_{intial}

where xfinalx_{final} is the final position of an object, and xintialx_{intial} is the object’s initial position.

Average Velocity

Average velocity is a measure of the speed of the movement of an object in a specific direction. It is a vector quantity, which means it has both magnitude and direction. For example, if a car travels north for 100 meters in 5 seconds, its average velocity is 20 meters per second north. Thus, it is defined by the formula:

Vaverage=x2x1t2t1=ΔxΔtV_{average}=\frac{x_2-x_1}{t_2-t_1}=\frac{\Delta x}{\Delta t}

Where, x2x1x_2-x_1 is the change in an objects displacement, and t2t1t_2-t_1 is the change in time, or time it took the object to travel from x1x_1 to x2x_2.

Practice Question 1

Alice drives from Town A to Town B, which are 120 km apart. She drives for 1.5 hours before reaching Town B. After staying in Town B for two hours, she drives back to Town A, taking 2 hours. What is her average velocity for the entire trip?

To solve this problem, we must first determine the displacement of Alice, and the time taken for her travels.

The problem tells us that Alice returns to her original position, meaning that her displacement is 00. Now finding the change in time between point 1 and 2 (which in this case are the same point):

t2=2t1=1.5t2t1=21.5=0.5t_2=2\qquad t_1=1.5\\t_2-t_1=2-1.5\\=0.5

Thus, we can substitute values into the average velocity formula:

Vaverage=00.5=0V_{average}=\frac{0}{0.5}\\=0

\therefore The average velocity of the journey is 0 km/h

Average Speed

Average speed is a scalar quantity that measures how fast an object is moving. Unlike average velocity, it does not account for the direction of travel. For instance, if a person walks around a block covering a total distance of 1 km in 10 minutes, their average speed is 6 km/h , regardless of their starting or ending point. Thus, its formula is:

Saverage=totaldistancetravelledtimetaken(t)S_{average}=\frac{total\:distance\:travelled}{time\:taken(t)}

It is also important to note, that because direction is not involved when calculating average speed, it can never be a negative value.

Similar to problems involving average velocity, we must ensure that the units used to calculate equations are consistent. For example, it is easiest to use kmkm and hourshours together, while metersmeters and secondsseconds are generally used together.

Practice Question 2

Alice drives from Town A to Town B, which are 120 km apart. She drives for 1.5 hours before reaching Town B. After staying in Town B for two hours, she drives back to Town A, taking 2 hours. What is her average speed for the entire trip?

In the previous example, we were given the same problem, except we were asked to calculate the average velocity of Alice. This time we must calculate her average speed. To find it, we must first determine the total distance she traveled and the time taken to do so.

Calculating total distance:

distance=120+120=240kmdistance=120+120\\=240km

Calculating total time taken:

time=1.5+2+2=5.5htime=1.5+2+2\\=5.5h

This is tricky. The formula requires the TOTAL time taken for the entire trip, and as Alice was stationary at town B for 2 hours, we must also include this in our calculations.

Now we can substitute values into the formula for average speed:

Saverage=2405.5=43.64S_{average}=\frac{240}{5.5}\\=43.64

\therefore Alice’s average speed for the trip was 43.64km/h43.64km/h

Return to Module 7: Motion and Rates